For f(x) = 0.01(2)x, find the average rate of change from x = 3 to x = 8.

A.0.08
B.0.496
C.2.48
D.5

find it at x = 8

find it at x = 3

subtract f(8) - f(3)

divide by 8-3, in other words divide by 5

and I can not do it because I do not understand your notation (still)

To find the average rate of change of a function, we need to find the difference in the values of the function over the given interval and divide it by the difference in the values of the independent variable over the same interval.

In this case, we are given the function f(x) = 0.01(2)^x and we need to find the average rate of change from x = 3 to x = 8.

Substituting these values into the function, we have f(3) = 0.01(2)^3 and f(8) = 0.01(2)^8.

The difference in the values of the function over the given interval is f(8) - f(3) = 0.01(2)^8 - 0.01(2)^3.

The difference in the values of the independent variable over the given interval is 8 - 3 = 5.

So, the average rate of change is (0.01(2)^8 - 0.01(2)^3) / 5.

To calculate this, we can simplify the equation:

0.01(2)^8 can be written as 0.01 * (2^8).

0.01(2)^3 can be written as 0.01 * (2^3).

So, the average rate of change is (0.01 * (2^8) - 0.01 * (2^3)) / 5.

Simplifying further, we have (0.01 * 256 - 0.01 * 8) / 5.

This becomes (2.56 - 0.08) / 5.

Finally, we have 2.48 / 5 = 0.496.

Thus, the average rate of change from x = 3 to x = 8 is 0.496.

Therefore, the correct answer is B. 0.496.