Fe3O4(s) + C(s) > CO2 + Fe
Balance the chemical reaction and calculate how many moles of Fe3O4 must be reacted to produce 440 gr CO2 (the > is an arrow)
Fe3O4(s) + 2C(s) > 2CO2 + 3Fe
mols CO2 = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols CO2 to mols Fe3O4.
To balance the chemical equation for the reaction Fe3O4(s) + C(s) > CO2 + Fe, you need to ensure that the number of atoms of each element is equal on both sides of the equation.
Let's start by balancing the carbon (C) atoms. There is only one carbon atom on the left side, so we need one on the right side as well. Therefore, we add a coefficient of 1 in front of CO2 in the balanced equation:
Fe3O4(s) + C(s) > 1CO2 + Fe
Next, let's balance the iron (Fe) atoms. There are three iron atoms on the left side, so we need three on the right side. We add a coefficient of 3 in front of Fe:
Fe3O4(s) + C(s) > CO2 + 3Fe
Now, let's balance the oxygen (O) atoms. There are four oxygen atoms in the Fe3O4 on the left side and two oxygen atoms in CO2 on the right side. Thus, we need four CO2 molecules to balance the oxygen atoms on the right side. We add a coefficient of 4 in front of CO2:
Fe3O4(s) + C(s) > 4CO2 + 3Fe
Finally, let's check the balance for hydrogen (H) atoms. There are no hydrogen atoms on either side of the equation, so we don't need to make any changes.
The balanced chemical equation is:
Fe3O4(s) + C(s) > 4CO2 + 3Fe
Now we can calculate the number of moles of Fe3O4 required to produce 440 g of CO2.
First, determine the molar mass of CO2: carbon (C) has a molar mass of 12.01 g/mol, and oxygen (O) has a molar mass of 16.00 g/mol. So the molar mass of CO2 is (12.01 g/mol + 2 * 16.00 g/mol) = 44.01 g/mol.
To calculate the number of moles, divide the given mass of CO2 by its molar mass:
Number of moles of CO2 = Mass of CO2 / Molar mass of CO2
= 440 g / 44.01 g/mol
≈ 10 moles
Based on the balanced equation, it shows that for every 4 moles of CO2 produced, 1 mole of Fe3O4 is consumed. Therefore, the number of moles of Fe3O4 required to produce 440 g of CO2 is:
Number of moles of Fe3O4 = Number of moles of CO2 / (4 moles of CO2 / 1 mole of Fe3O4)
= 10 moles / (4/1)
= 2.5 moles
Therefore, approximately 2.5 moles of Fe3O4 must be reacted to produce 440 g of CO2.