A car traveling at a velocity of 2m/s undergoes an acceleration of 4.5m/s2 over a distance of 340m.How fast will it be going after the acceleration?

To determine the final velocity of the car after undergoing the given acceleration, we can use the formula:

v^2 = u^2 + 2as

Where:
v = final velocity
u = initial velocity
a = acceleration
s = distance traveled

In this case:
Initial velocity (u) = 2 m/s
Acceleration (a) = 4.5 m/s^2
Distance traveled (s) = 340 m

First, we need to find the square of the initial velocity:

u^2 = 2^2 = 4 m^2/s^2

Next, we can substitute the values into the formula and solve for the final velocity (v):

v^2 = 4 + 2(4.5)(340)
v^2 = 4 + 3060
v^2 = 3064

To find the value of v, the square root of 3064 is taken:

v = √3064 ≈ 55.34 m/s

Therefore, the car will be traveling at approximately 55.34 m/s after the acceleration.