3d-10=5 (d-4)

i don't understand to solve the problem...
plz help

*how

3d-10=5 (d-4)

3d - 10 = 5d - 20

Combine like terms.
Add 20 to both sides.
Subtract 3d from both sides.

10 = 2d
5 = d

To solve the equation 3d - 10 = 5(d - 4), you'll need to use the distributive property and apply the order of operations (PEMDAS/BODMAS). Let's break it down step by step:

1. Distribute the 5 to the terms inside the parentheses:
3d - 10 = 5d - 20

2. To isolate the variable terms on one side of the equation, let's subtract 3d from both sides:
(3d - 3d) - 10 = (5d - 3d) - 20
Simplify:
-10 = 2d - 20

3. Next, let's move the constant term (-20) to the other side of the equation by adding 20 to both sides:
-10 + 20 = 2d - 20 + 20
Simplify:
10 = 2d

4. Finally, divide both sides of the equation by 2 to solve for d:
10/2 = 2d/2
Simplify:
5 = d

Therefore, the value of d that satisfies the equation 3d - 10 = 5(d - 4) is d = 5.