negative one times the sum of twice a number and 3 is equal to two times the difference of -4 times the number and 3. what is the number?
Written in Math, that would be
-1(2x + 3) = -4x - 3
-2x - 3 = -4x - 3
2x = 0
x = 0
check:
the sum of twice the number and 3 = 2(0) + 3 = 3
-1 times that = -3
the difference between -4 times the number and 3
= -4(0) - 3 = -3
yup, the answer is correct
written in math would be
-1(2x+3)=2(-4x-3)
-2x-3=-8x-6
-3=-6x-6
3=-6x
-0.5=x
misread the question, missed the "equal to two times"
To solve this equation, let's break it down step by step.
Step 1: Define the unknown number.
Let's represent the unknown number as "x."
Step 2: Translate the given sentence into an equation.
"Negative one times the sum of twice a number and 3 is equal to two times the difference of -4 times the number and 3."
Written as an equation, this can be represented as:
-1 * (2x + 3) = 2 * (-4x - 3)
Step 3: Solve the equation.
Distribute -1 and 2 respectively:
-2x - 3 = -8x - 6
Combine like terms:
-2x + 8x = -6 + 3
6x = -3
Divide both sides of the equation by 6:
x = -3/6
Simplify the fraction:
x = -1/2
Therefore, the number is -1/2.