A car travels with uniform velocity of 30m for 5 secs and then comes to rest in the next 10sec with the aid of a diagram calculate the deceleration of the car
To calculate the deceleration of the car, we need to use the formula:
Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)
In this case, the car goes from a uniform velocity of 30 m/s to rest, which means its final velocity (vf) is 0 m/s. The initial velocity (vi) is 30 m/s and the time taken (Δt) for the car to come to rest is 10 seconds.
Using the formula, we can calculate the change in velocity (Δv):
Δv = vf - vi
Δv = 0 - 30
Δv = -30 m/s
Now, we can substitute the values into the formula to find the deceleration (a):
a = Δv / Δt
a = -30 m/s / 10 s
a = -3 m/s²
So, the deceleration of the car is -3 m/s².
To calculate the deceleration of the car, we need to use the equation of motion.
First, let's understand the situation with the help of a diagram:
Diagram:
_____/¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯\____________/‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾\___________
5 sec 10 sec
In the above diagram, the car travels with a uniform velocity of 30 m for 5 seconds, indicated by the horizontal line. After that, the car comes to rest in the next 10 seconds, as shown by the downward slope.
Now, let's calculate the deceleration of the car.
We know the formula for acceleration is:
Acceleration (a) = Change in velocity (Δv) / Time taken (Δt)
In this case, the initial velocity (u) is 30 m/s, and the final velocity (v) is 0 m/s because the car comes to rest.
Initial velocity (u) = 30 m/s
Final velocity (v) = 0 m/s
Time taken (Δt) = 10 seconds
We can rearrange the formula to solve for acceleration:
Acceleration (a) = (v - u) / Δt
Substituting the given values:
Acceleration (a) = (0 m/s - 30 m/s) / 10 sec
Simplifying the equation:
Acceleration (a) = -30 m/s / 10 sec
Finally, we get:
Acceleration (a) = -3 m/s²
The negative sign indicates that the car is decelerating.
Therefore, the deceleration of the car is 3 m/s².