Scott is rolling down a 30° slope on his skateboard.The total mass of Scott and the skateboard is 75 kg. The rolling friction between the skateboard wheels and the concrete is 9 N acting backward against the skateboard. The drag force due to air resistance is 11 N acting backward against Scott. What is Scott’s acceleration?
weight component down hill = 75*9.81 * sin 30
a = (75*9.81*.5 - 11 -9 )/75
Scott is stupoood
Well, with Scott rolling down a slope on his skateboard, it seems like he's really going downhill in life. But let's crunch some numbers to calculate his acceleration.
To start off, we need to find the net force acting on Scott. The net force is the sum of all the forces acting on him. In this case, we have two forces: the rolling friction and the drag force.
The rolling friction force is given as 9 N, acting backward against the skateboard. Since Scott is not pushing himself forward, this force acts against his motion.
The drag force due to air resistance is given as 11 N, also acting backward against Scott. This force slows him down and tries to keep him from reaching his full potential.
To find the net force, we subtract these forces acting against Scott's motion:
Net force = Drag force - Rolling friction force
Net force = 11 N - 9 N
Net force = 2 N
Now that we know the net force, we can use Newton's second law (F = ma) to find Scott's acceleration. The mass of Scott and the skateboard is given as 75 kg.
Net force = mass * acceleration
2 N = 75 kg * acceleration
Now we just need to solve for acceleration:
acceleration = 2 N / 75 kg
acceleration = 0.0267 m/s²
So Scott's acceleration downhill is approximately 0.0267 m/s². It seems like he's not going downhill in life as fast as he'd like, but hey, at least he's moving forward!
To find Scott's acceleration, we need to use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
The net force is the vector sum of all the forces acting on the object. In this case, the only two forces acting on Scott are the rolling friction force and the drag force.
The rolling friction force is given as 9 N acting backward against the skateboard, and the drag force is given as 11 N acting backward against Scott.
Since both forces are acting in the opposite direction of motion, we can subtract them to find the net force:
Net force = Drag force - Rolling friction force
= -11 N - (-9 N)
= -11 N + 9 N
= -2 N
The negative sign indicates that the net force is acting in the opposite direction of motion.
Now, we can use Newton's second law:
Net force = mass × acceleration
Rearranging the formula to solve for acceleration:
Acceleration = Net force / mass
= -2 N / 75 kg
= -0.027 m/s²
The negative sign indicates that Scott is experiencing deceleration (a decrease in speed) due to the opposing forces. The acceleration value is approximately -0.027 m/s².