If one third of 100 gm of 27% of aqueous solution is taken in a beaker and 10 gm of sugar is added to it,the concentration of resulting solution is.....
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The answer is 43.84 %
To find the concentration of the resulting solution, we need to calculate the amount of solute (sugar) in the new solution and divide it by the total solution volume.
Let's break down the problem step by step:
Step 1: Calculate the amount of solute (sugar) in the original aqueous solution.
Since we have 27% aqueous solution, it means that 27% of the solution is sugar and the remaining 73% is water.
Therefore, the amount of sugar in 100 gm of solution is 27 gm (since 27% of 100 gm is 27 gm).
Step 2: Determine the amount of solution taken in the beaker.
We are taking one third (1/3) of the original solution, which means we are taking 100 gm / 3 = 33.33 gm of solution in the beaker.
Step 3: Add 10 gm of sugar to the solution in the beaker.
This means we are adding an additional 10 gm of sugar to the beaker.
Step 4: Calculate the total amount of sugar in the resulting solution.
The total amount of sugar in the resulting solution is the sum of the sugar already in the beaker (27 gm) and the added sugar (10 gm), which equals 37 gm.
Step 5: Find the concentration of the resulting solution.
To find the concentration, we need to divide the total amount of sugar (37 gm) by the total solution volume. The total solution volume is the amount of solution taken in the beaker (33.33 gm) plus the weight of the sugar added (10 gm), which equals 43.33 gm.
Concentration = (Amount of sugar / Total solution volume) * 100
Concentration = (37 gm / 43.33 gm) * 100
Concentration ≈ 85.40%
Therefore, the concentration of the resulting solution is approximately 85.40%.