If the first term of an Ap is equal to one half of the common differences,d, find the 8th term of the Ap
a=1/1/2=3/2
D=2
T8=a+7d equation 1
T8=3/2+7(2)
T8=3/2+14/1
T8=17d/2
It's 17d/2 actually
Please how did u get to the final answer 15d/2
Please John could you expanciate more on your answer
given: a = (1/2)d or d/2
term(8) = a + 7d
= d/2 + 7d
= 15d/2
How did u get the final answer 15d/2
d/2+7. L.C.M =2
———
2. =d+14d
———. = 15d/2
2