if a car was traveling 60 miles an hour and hit and in movable wall instantaneously stopping how many gravities of force would be involved
for any momentum to instantly (not instantaneously!) go to zero, there must be infinite deceleration.
To calculate the number of g-forces experienced when a car traveling at a certain speed hits an immovable wall, we need to convert the speed into acceleration first.
The formula to calculate acceleration is:
acceleration = change in velocity / time
Since the car instantaneously stops, the change in velocity is equal to its initial velocity. Therefore, the acceleration can be calculated as:
acceleration = 60 miles per hour / 1 hour
To convert this to a more useful unit, we need to convert miles per hour to feet per second (fps):
1 mile = 5280 feet
1 hour = 3600 seconds
Using these conversion factors, we can calculate the acceleration:
acceleration = (60 miles/hour) * (5280 feet/mile) / (1 hour) / (3600 seconds/hour)
Simplifying this equation, we get:
acceleration = 88 feet per second squared
Now, to calculate the number of g-forces, we need to divide the acceleration by the acceleration due to gravity (32.2 feet per second squared):
g-forces = acceleration / (acceleration due to gravity)
Substituting the values, we get:
g-forces = 88 feet per second squared / 32.2 feet per second squared
Simplifying this equation, we get:
g-forces ≈ 2.73 g
So, if a car traveling at 60 miles per hour hits an immovable wall and instantaneously stops, it would experience approximately 2.73 g-forces of force.