On the planet mars, a free falling object released from rest falls 4m in 1s and is moving at 8m/s at that time. How fast would such an object moving after 2 seconds? 3 seconds?
To find the speed of a free-falling object on Mars after a given time, we need to understand the acceleration due to gravity on the planet. The acceleration due to gravity on Mars is approximately 3.71 m/s^2 (compared to 9.8 m/s^2 on Earth).
Now, let's break down the problem step by step.
1. First, we need to find the object's acceleration. Since the object is in free fall, its acceleration is equal to the acceleration due to gravity on Mars, which is 3.71 m/s^2.
2. Next, we can calculate the object's velocity at different times using the following formula:
v = u + at
where:
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time.
For the given problem, the object is released from rest, so the initial velocity (u) is 0 m/s.
3. Using the formula, we can calculate the velocity at different times.
a) After 1 second:
v = 0 + (3.71 m/s^2) * (1 s)
v = 3.71 m/s
b) After 2 seconds:
v = 0 + (3.71 m/s^2) * (2 s)
v = 7.42 m/s
c) After 3 seconds:
v = 0 + (3.71 m/s^2) * (3 s)
v = 11.13 m/s
Therefore, after 2 seconds, the object would be moving at a speed of 7.42 m/s, and after 3 seconds, it would be moving at a speed of 11.13 m/s.