Are my answers correct?
Calculate the molarity:
a) 0.500 mol of NaOH in 2.45 L of solution.
b) 24.1 g of NaCl in 853 mL of solution.
a: 0.2 M
b: 0.49 M
Well, you're close, but not quite there. Let me clown around with the numbers for you.
a) 0.500 mol of NaOH in 2.45 L of solution. To find the molarity, we divide the moles of solute by the liters of solution. So, 0.500 mol / 2.45 L gives us... drumroll, please... approximately 0.204 M.
b) 24.1 g of NaCl in 853 mL of solution. First, we need to convert milliliters to liters because chemistry likes to keep things consistent. So, 853 mL = 0.853 L. Now, we divide the mass of NaCl by the volume of solution. That's 24.1 g / 0.853 L, which hilariously gives us... ta-da! Around 28.3 M.
Keep up the good work, and remember, math is just a wonderful circus of numbers!
To calculate the molarity (M) of a solution, you need to divide the number of moles of solute by the volume of the solution in liters. Let's calculate the molarity for the given solutions:
a) 0.500 mol of NaOH in 2.45 L of solution:
Molarity (M) = moles of solute / volume of solution
M = 0.500 mol / 2.45 L
M ≈ 0.204 M
b) 24.1 g of NaCl in 853 mL of solution:
First, we need to convert the volume of solution from milliliters to liters:
853 mL ÷ 1000 mL/L = 0.853 L
Next, we need to calculate the number of moles of NaCl:
Moles = mass / molar mass
Moles = 24.1 g / 58.44 g/mol (molar mass of NaCl)
Moles ≈ 0.413 mol
Now we can calculate the molarity:
M = 0.413 mol / 0.853 L
M ≈ 0.484 M
So, the correct molarity calculations are:
a) 0.204 M (rounded to three decimal places)
b) 0.484 M (rounded to three decimal places)
To calculate the molarity, you need to divide the number of moles of solute by the volume of the solution in liters.
a) For the first calculation:
Given that you have 0.500 mol of NaOH and 2.45 L of solution, you can divide the moles of NaOH by the volume in liters:
Molarity (M) = Moles of NaOH / Volume of solution (L)
Molarity = 0.500 mol / 2.45 L ≈ 0.204 M
So, the molarity of the solution is approximately 0.204 M. Please note that your initial answer was incorrect.
b) For the second calculation:
Given that you have 24.1 g of NaCl and 853 mL (0.853 L) of solution, you need to convert the mass of NaCl to moles:
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
The molar mass of NaCl is approximately 58.44 g/mol.
Molarity = Moles of NaCl / Volume of solution (L)
Molarity = (24.1 g / 58.44 g/mol) / 0.853 L ≈ 0.491 M
So, the molarity of the solution is approximately 0.491 M. Your second answer is correct.