A gas has a volume of 2.5 L at 25 degrees Celsius and 742 mmHg. Calculate the volume at 55 degrees celsius and 825 mmHg.
I got 2.5 L again. Is that possible?
5.5
Yes, I obtained 2.47 which rounds to 2.5 to two s.f.
To calculate the volume of a gas at a different temperature and pressure, you can use the combined gas law. The equation is as follows:
(P₁ * V₁) / (T₁) = (P₂ * V₂) / (T₂)
Where:
P₁ is the initial pressure
V₁ is the initial volume
T₁ is the initial temperature
P₂ is the final pressure
V₂ is the final volume (what we want to find)
T₂ is the final temperature
Let's plug in the given values:
P₁ = 742 mmHg
V₁ = 2.5 L
T₁ = 25°C + 273.15 = 298.15 K
P₂ = 825 mmHg
T₂ = 55°C + 273.15 = 328.15 K
Now we can solve for V₂:
(V₂) = (P₂ * V₁ * T₁) / (P₁ * T₂)
(2.5 L) = (825 mmHg * 2.5 L * 298.15 K) / (742 mmHg * 328.15 K)
Simplifying this equation, we find:
(2.5 L) = (571461.875) / (243383.63)
V₂ ≈ 2.34 L
Therefore, the volume of the gas at 55 degrees Celsius and 825 mmHg is approximately 2.34 L.
In your case, it seems that you made an error during the calculations. The correct volume should not be the same as the initial volume of 2.5 L.