What volume of 0.159 M Na3PO4 solution is necessary to completely react with 92.6 mL of 0.119 M CuCl2?
1. Write and balance the equation.
2Na3PO4 + 3CuCl2 ==> Cu3(PO4)2 + 6NaCl
2. mols CuCl2 - M x L = ?
3. Using the coefficients in the balanced equation, convert mols CuCl2 to mols Na3PO4.
4. M Na3PO4 = mols Na3PO4/L Na3PO4.
You know M and mols, solve for L
To find the volume of the Na3PO4 solution necessary to react with the CuCl2 solution, we need to use the balanced chemical equation for the reaction and the stoichiometry.
The balanced chemical equation for the reaction between Na3PO4 and CuCl2 is:
3Na3PO4 + 2CuCl2 -> Cu3PO4 + 6NaCl
From the balanced equation, we can see that:
- 3 moles of Na3PO4 react with 2 moles of CuCl2
- This means that the ratio of Na3PO4 to CuCl2 is 3:2
Now, we can use the given concentrations and volumes to calculate the moles of CuCl2 that react.
Moles of CuCl2 = Concentration of CuCl2 x Volume of CuCl2 = 0.119 M x 92.6 mL = 0.119 M x 0.0926 L = 0.01101 moles
Since the ratio of Na3PO4 to CuCl2 is 3:2, we can set up a proportion using the mole ratios:
3 moles Na3PO4 / 2 moles CuCl2 = X moles Na3PO4 / 0.01101 moles CuCl2
Solving for X, we get:
X = (3/2) x 0.01101 = 0.016515 moles Na3PO4
Now, we can calculate the volume of the Na3PO4 solution using its concentration:
Volume of Na3PO4 = Moles of Na3PO4 / Concentration of Na3PO4
Volume of Na3PO4 = 0.016515 moles / 0.159 M = 0.10392 L
Finally, we can convert the volume to milliliters:
Volume of Na3PO4 = 0.10392 L x 1000 mL/L ≈ 103.92 mL
Therefore, the volume of the 0.159 M Na3PO4 solution necessary to completely react with 92.6 mL of 0.119 M CuCl2 is approximately 103.92 mL.
To determine the volume of the Na3PO4 solution needed to react with the CuCl2 solution, we first need to balance the chemical equation for the reaction. The reaction between Na3PO4 and CuCl2 can be represented as follows:
2 Na3PO4 + 3 CuCl2 -> 6 NaCl + Cu3PO4
From the balanced equation, we can see that 2 moles of Na3PO4 react with 3 moles of CuCl2. This indicates that the stoichiometric ratio of Na3PO4 to CuCl2 is 2:3.
Next, we can calculate the number of moles of CuCl2 in the given volume of the solution. To do this, we use the equation:
moles = concentration (M) * volume (L)
moles of CuCl2 = 0.119 M * 0.0926 L
moles of CuCl2 = 0.0109954 mol
Since we have a 2:3 stoichiometric ratio, we know that 3 moles of CuCl2 react with 2 moles of Na3PO4. Therefore, we can set up a proportion to find the number of moles of Na3PO4 needed:
(3 moles CuCl2 / 2 moles Na3PO4) = (0.0109954 mol CuCl2 / x mol Na3PO4)
Solving for x, we get:
x = (2 moles Na3PO4 * 0.0109954 mol CuCl2) / (3 moles CuCl2)
x = 0.0073328 mol Na3PO4
Now, we can calculate the volume of the Na3PO4 solution needed. Using the equation:
volume (L) = moles / concentration (M)
volume of Na3PO4 = 0.0073328 mol / 0.159 M
volume of Na3PO4 = 0.04607 L
To convert the volume to mL:
volume of Na3PO4 = 0.04607 L * 1000 mL/L
volume of Na3PO4 = 46.07 mL
Therefore, approximately 46.07 mL of 0.159 M Na3PO4 solution is necessary to completely react with 92.6 mL of 0.119 M CuCl2.