A transformer has a primary coil with 600 turns and a secondary coil with 300 turns. If the output voltage is 320 volts, what is the input voltage?
A. 8 volts
B. 150 volts
C. 640 volts
D. 600 volts
half
To find the input voltage of the transformer, we can use the formula for transformer voltage ratio.
The voltage ratio is given by:
(V₂ / V₁) = (N₂ / N₁),
where V₂ is the secondary voltage, V₁ is the primary voltage, N₂ is the number of turns in the secondary coil, and N₁ is the number of turns in the primary coil.
Using the values given:
(320 / V₁) = (300 / 600).
Simplifying the equation:
(320 / V₁) = (1 / 2).
To find the input voltage, we can rearrange the equation:
320 = V₁ / 2.
Multiplying both sides by 2:
640 = V₁.
Therefore, the input voltage is 640 volts.
So, the correct answer is C. 640 volts.
To find the input voltage of the transformer, we can use the formula that relates the turns ratio of the transformer to the voltage ratio. The formula is:
Voltage ratio = (Number of turns in secondary coil) / (Number of turns in primary coil)
In this case, the voltage ratio is given as 320 volts (output voltage) and the turns ratio is given as 300 turns (secondary coil) divided by 600 turns (primary coil). Let's plug in the values:
320 volts = (300 turns) / (600 turns)
To find the input voltage, we can cross multiply and solve for it:
320 volts * 600 turns = 300 turns * input voltage
192,000 = 300 * input voltage
Divide both sides by 300:
(input voltage) = 192,000 / 300
Now, we can simplify:
(input voltage) = 640 volts
Therefore, the input voltage of the transformer is 640 volts. So the correct answer is option C.