when potassium in water are combined they produced 4000.0 kJ of heat along with potassium hydroxide and hydrogen gas. how much energy would be produced if you dumped a 1.00 kg chunk of potassium into a swimming pool? s this reaction what is the enthalpy change?
To determine the amount of energy produced when a 1.00 kg chunk of potassium is dumped into a swimming pool, we need to use the concept of molar enthalpy change.
First, we need to convert the mass of potassium (1.00 kg) into moles. The molar mass of potassium (K) is approximately 39.10 g/mol.
Number of moles of potassium = mass of potassium / molar mass of potassium
= 1000 g / 39.10 g/mol
= 25.57 mol
Since the given enthalpy change is for 1 mole of potassium, we can calculate the energy produced for 25.57 moles, using the given value of 4000.0 kJ.
Energy produced = enthalpy change * number of moles
= 4000.0 kJ * 25.57
≈ 102,280 kJ
Therefore, dumping a 1.00 kg chunk of potassium into a swimming pool would produce approximately 102,280 kJ of energy.
As for the enthalpy change, the given value of 4000.0 kJ represents the energy produced when 1 mole of potassium reacts with water to form potassium hydroxide and hydrogen gas. Thus, the enthalpy change for this reaction is 4000.0 kJ/mol.