The sum of three consecutive even integers is 54. What is the middle integer .
Let's set up an equation to solve this problem.
Let's assume the first even integer as 'x'.
Since they are consecutive even integers, the second even integer would be 'x + 2' and the third even integer would be 'x + 4'.
According to the problem, the sum of these three consecutive even integers is 54:
x + (x + 2) + (x + 4) = 54
Now, let's simplify the equation:
3x + 6 = 54
Subtract 6 from both sides:
3x = 48
Divide both sides by 3:
x = 16
Therefore, the middle integer is x + 2, which is 16 + 2 = 18.
To find the middle integer, we need to understand the sequence of three consecutive even integers. Let's assume the first even integer is 'x'. Since they are consecutive, the next even integer will be 'x + 2' and the one after that will be 'x + 4'.
Now, we know that the sum of these three consecutive even integers is 54. Therefore:
x + (x + 2) + (x + 4) = 54
Let's simplify this equation:
3x + 6 = 54
Now, we need to isolate the 'x' term by subtracting 6 from both sides:
3x = 54 - 6
3x = 48
Next, divide both sides of the equation by 3 to solve for 'x':
x = 48 / 3
x = 16
So, the first even integer is 16. The middle integer will be 'x + 2', which is:
16 + 2 = 18
Therefore, the middle integer in the sequence is 18.
Middle integer = x, then others are x-1 and x+1.
(x-1) + x + (x+1) = 54
Solve for x.