You are pulling handle of a wagon with a force of 270N. The handle makes an upward 35 degrees angle with the ground. The loaded wagon has a mass of 95kg.
1.what is the weight of the wagon?
2.How much of your applied force pulls the wagon forward?
3.what is the normal force acting on the wagon?
To answer these questions, we need to understand the concepts of weight, force components, and the normal force.
1. Weight of the Wagon:
The weight of an object is given by the formula: weight = mass x gravitational acceleration.
Given that the mass of the wagon is 95 kg and the gravitational acceleration is approximately 9.8 m/s^2, we can calculate the weight of the wagon as follows:
Weight = 95 kg x 9.8 m/s^2 = 931 N
Therefore, the weight of the wagon is 931 Newtons.
2. Force pulling the wagon forward:
To determine how much of your applied force pulls the wagon forward, we need to calculate the horizontal component of the force. Since the handle makes an upward angle with the ground, we can use trigonometry to find the horizontal component.
The horizontal component of a force is given by the formula: horizontal component = force x cosine(angle).
Given that the force you are applying is 270 N and the angle is 35 degrees, we can calculate the horizontal component as follows:
Horizontal Component = 270 N x cos(35 degrees)
Calculating this value gives us the force pulling the wagon forward.
3. Normal force acting on the wagon:
The normal force is the force exerted on an object perpendicular to the surface it is resting on. In this case, since the wagon is on the ground, the normal force is the force exerted by the ground on the wagon.
The normal force is equal in magnitude but opposite in direction to the force exerted by the wagon on the ground.
Therefore, the normal force acting on the wagon is equal to the weight of the wagon, which we calculated earlier as 931 Newtons.
In summary:
1. The weight of the wagon is 931 Newtons.
2. To find the amount of your applied force that pulls the wagon forward, use the formula force x cosine(angle).
3. The normal force acting on the wagon is equal to the weight of the wagon.