Last questions, thanks for everything
There are 21 plates of tomato sandwiches, 27 plates of cheese sandwiches, and 12 plates of beef sandwiches on a buffet table.
If a guest randomly picks a single plate, what is the probability that he gets tomato or cheese sandwiches?
A)0.10
B)0.25
C)0.48
D)0.80
D?
Left-handed batters
Freshmen: 4
Sophomore: 6
Junior: 5
Senior: 4
Right-handed batters
Freshmen: 13
Sophomore: 10
Junior: 11
Senior: 12
A)11/65 <- OR THIS ONE BECAUSE ITS ONLY 11 JUNIORS THAT ARE RIGHTHANDED
B)14/65
C)16/65 <--- 5(J)+11(RH) = 16
D)51/65
D is correct.
What is the question related to the batters?
Wrong for question 2 answer is D
To find the probability, we need to calculate the number of favorable outcomes (plates of tomato or cheese sandwiches) divided by the total number of possible outcomes (the total number of plates on the buffet table).
In this case, the number of favorable outcomes is the sum of the plates of tomato sandwiches (21) and cheese sandwiches (27), which is 21 + 27 = 48.
The total number of plates on the buffet table is the sum of tomato sandwiches (21), cheese sandwiches (27), and beef sandwiches (12), which is 21 + 27 + 12 = 60.
Therefore, the probability of getting a tomato or cheese sandwich is 48/60 = 0.8.
So, the correct answer is option D) 0.80.
Now let's move on to the second question about left-handed and right-handed batters.
To determine the probability, we need to calculate the number of favorable outcomes (junior right-handed batters) divided by the total number of possible outcomes (all batters).
In this case, the number of favorable outcomes is the number of junior right-handed batters, which is 11.
The total number of possible outcomes is the total number of all batters, which is the sum of left-handed and right-handed batters in each category:
- Freshmen: 4 left-handed + 13 right-handed = 17
- Sophomore: 6 left-handed + 10 right-handed = 16
- Junior: 5 left-handed + 11 right-handed = 16
- Senior: 4 left-handed + 12 right-handed = 16
The total number of all batters is 17 + 16 + 16 + 16 = 65.
Therefore, the probability of selecting a junior right-handed batter is 11/65.
So, the correct answer is option A) 11/65.
I hope this helps! Let me know if you have any more questions.