a boat starts sailing on monday 10:00 at harbour A and sail 600 km due north.later it turns due east for a further 420 km to reach harbour B on tuesday at 12:00.what is the total distance travelled from A to B
d = 600 + 420 = 1020 km.
To find the total distance traveled from Harbor A to Harbor B, we need to calculate the distance traveled in each leg of the journey and then add them together.
In the first leg, the boat sails 600 km due north. As it is a straight path, the distance traveled in this leg is simply 600 km.
In the second leg, the boat turns due east and sails a further 420 km. Again, since it is a straight path, the distance traveled in this leg is 420 km.
To find the total distance traveled, we add the distances of both legs together: 600 km + 420 km = 1020 km.
Therefore, the total distance traveled from Harbor A to Harbor B is 1020 km.