A truck travels beneath an airplane that is moving 140 Km/h at an angle of 15 degree to the ground.

How fast must the truck travel to stay beneath the airplane?
Answer in units of Km/h.

What is 140*cos15?

To find the speed at which the truck must travel to stay beneath the airplane, we need to consider the components of the airplane's velocity.

The airplane's velocity can be broken down into two components: horizontal and vertical.

The horizontal component of the airplane's velocity is given by V_horizontal = V_airplane * cos(angle), where V_airplane is the speed of the airplane and angle is the angle it makes with the ground. Substituting the given values, we have V_horizontal = 140 Km/h * cos(15 degrees).

The vertical component of the airplane's velocity is given by V_vertical = V_airplane * sin(angle), where V_airplane is the speed of the airplane and angle is the angle it makes with the ground. Substituting the given values, we have V_vertical = 140 Km/h * sin(15 degrees).

In order for the truck to stay beneath the airplane, its velocity in the horizontal direction must be equal to the horizontal component of the airplane's velocity. Therefore, the truck must travel at a speed of V_horizontal = 140 Km/h * cos(15 degrees).

Calculating this value, we get:

V_horizontal = 140 Km/h * cos(15 degrees)
≈ 133.85 Km/h

Therefore, the truck must travel at a speed of approximately 133.85 Km/h to stay beneath the airplane.