Vehicle can travel 0-60mph in 7.6 sec. From a dead stop, what is the highest rate of speed vehicle can reach and decelerate to 10mph in 500 ft distance?
60mi/h=60mi/3600s. * 1600m/mi = 26.7 m/s
10mi/h = 10/60 * 26.7 = 4.44 m/s.
500Ft. * 1m/3.3Ft = 152 m.
a = (Vf-Vo)/t = (26.7-0)/7.6 = 3.51 m/s.
Vf^2 = Vo^2 + 2a*d.
Vo^2 = Vf^2-2a*d = 4.44 - (-8.88)*152 =
1354.2
Vo = 36.8 m/s. = Max. initial velocity
for the given stopping distance.