how much oxygen gas wil be produce from the decomosition of 50 grams of pottasium chlorate

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2KClO3 ==> 2KCl + 3O2

mols KClO3 = grams/molar mass = ?
Using the coefficients in the balanced equation convert mols KClO3 to mols O2
What do you mean by "How much"? If you want grams, that is grams = mols O2 x molar mass O2.
If you want volume, that is L = mols O2 x 22.4 L/mol = ?L

.306 moles of O2

Mol's of KClO3=122.6 grams

To determine the amount of oxygen gas produced from the decomposition of potassium chlorate, we need to use stoichiometry. The balanced chemical equation for the decomposition of potassium chlorate (KClO3) is:

2KClO3(s) → 2KCl(s) + 3O2(g)

From the equation, we see that two moles of potassium chlorate produce three moles of oxygen gas. Therefore, we need to convert the mass of potassium chlorate (KClO3) to moles and then use the stoichiometric ratio to find the moles of oxygen gas produced.

Step 1: Calculate the molar mass of potassium chlorate (KClO3):
- K (potassium) = 39.10 g/mol
- Cl (chlorine) = 35.45 g/mol
- O (oxygen) = 16.00 g/mol

Molar mass of KClO3 = (39.10 + 35.45 + (16.00 * 3)) g/mol = 122.55 g/mol

Step 2: Convert the mass of potassium chlorate to moles:
Number of moles = Mass / Molar mass

Number of moles of KClO3 = 50 g / 122.55 g/mol = 0.408 moles

Step 3: Use the stoichiometric ratio to find the moles of oxygen gas produced:
From the balanced equation, we know that two moles of KClO3 produce three moles of O2.

Number of moles of O2 = Number of moles of KClO3 * (3 moles of O2 / 2 moles of KClO3)
= 0.408 moles * (3 / 2)
= 0.612 moles

Step 4: Convert the moles of oxygen gas to grams:
Mass = Number of moles * Molar mass

Mass of O2 = 0.612 moles * 32.00 g/mol = 19.584 grams

Therefore, approximately 19.584 grams of oxygen gas will be produced from the decomposition of 50 grams of potassium chlorate.