Solve each system 6x-2y=10 and 3x-2=y

No solution. If you rearrange things a bit, you have

6x-2y=10
3x-y=2

Double the 2nd equation and you have

6x-2y=4

There's no way 6x-2y can be both 10 and 4.

To solve the given system of equations:

Equation 1: 6x - 2y = 10
Equation 2: 3x - 2 = y

We can solve this system by using the method of substitution. Here's how:

Step 1: Solve Equation 2 for y in terms of x:
3x - 2 = y
y = 3x - 2

Step 2: Substitute the value of y from Equation 2 into Equation 1:
6x - 2(3x - 2) = 10
6x - 6x + 4 = 10
4 = 10
This equation is not possible, which means the system of equations has no solution.

Therefore, the given system of equations is inconsistent and has no solution.