A bullet leaves a rifle with a velocity of 100 m/s and the rifle mass 2.5 kg recoils with a velocity of 1 m/s. Find the mass of the bullet. PLEASEEEE HELP ME.👏
according to law of conservation of momentum
MU + mu = MV + mv
Let M = 2.5 kg
m = m kg
initial velocity = 0 ( cause both were at rest before firing)
V = -1 m/s (it acts in opp. direction)
v = 100 m/s
2.5 X 0 + m x 0 = 2.5 x -1 + m X 100
0 = -2.5 + 100m
2.5 = 100m
25/1000 or 0.025 = m <= answer
Please understand this question
V=0
V=-1m/s
V=100m/s
2.5*0+ mv=0
=2.5*-1+m*100
0=-2.5+100m
2.5=100m
25/1000 or 0.025=m
*this is the sine of multiply ✖
All the answers above are wrong..
We should divide 25 with 10000.....
then the answer is 0.25kg
but u they all divided 25 from 1000...
hence got wrong answers
To find the mass of the bullet, we can use the principle of conservation of momentum.
The principle of conservation of momentum states that the total momentum before an event is equal to the total momentum after the event, assuming no external forces are acting on the system.
In this case, the system is the bullet and the rifle. Before the bullet is fired, the total momentum of the system is zero because both the bullet and the rifle are at rest. After the bullet is fired, the total momentum is also zero because the bullet and the rifle move in opposite directions with equal magnitudes of momentum.
Let's denote the mass of the bullet as m_bullet and the velocity of the bullet as v_bullet. The mass of the rifle is given as 2.5 kg and the velocity of the rifle after firing is 1 m/s. The velocity of the bullet after firing is 100 m/s (assuming no air resistance).
Using the principle of conservation of momentum:
Total momentum before = Total momentum after
(0) = (m_bullet * v_bullet) + (2.5 kg * 1 m/s)
Since the total momentum is zero, we can ignore the term (2.5 kg * 1 m/s) on the right side of the equation.
Now we have:
0 = m_bullet * v_bullet
Since the velocity of the bullet is given as 100 m/s:
0 = m_bullet * 100 m/s
To solve for m_bullet, we divide both sides of the equation by 100 m/s:
0 / 100 m/s = m_bullet
Therefore, the mass of the bullet is 0 kg.
However, it is important to note that this answer seems unrealistic. It is possible that there might be a mistake or missing information in the question.
The preamble the problem and experience to help out in the past year and the problem.
A bullet leaves a rifle with a velocity of 100 m/s and the rifle of mass 2.5 kg recoils with a velocity of 1 m/s. the mass of the bullet can be determined by the mass of conservation of momentum.
According to the conservation of the momentum is given by \bold{m 1 v 1=m 2 v 2}m1v1=m2v2
Hence by considering the mass of the bullet as m1 and the rifle with the mass of m2 and hence v1 is the velocity of the bullet and the v2 be the velocity of the rifle.
m 1 v 1=m 2 v 2m1v1=m2v2
m 1=\frac{m 2 v 2}{v 1}m1=
v1
m2v2
m 1=\frac{2.5 * 1}{100}m1=
100
2.5∗1
m1 = 0.025kg
m1 = 25g
Hence the mass of the bullet is generalised and found as 25g.
Mass of bullet is 25g