complete the molecular equation, determine the products and write out the balanced net ionic equation.
- Ni(NO3)2(aq) + FeCl3(aq)-->
- Ba(ClO4)2(aq) + Na2SO4(aq)-->
-2NH4Br(aq) + Pb(ClO3)2(aq)-->
-2NaOH(aq) + Ba(ClO4)2(aq)-->
To complete the molecular equations, determine the products, and write out the balanced net ionic equations for the given reactions, we need to first understand the solubility of the compounds involved. This will help us identify the state of the substances (solid, liquid, gas, or aqueous) and determine if they dissociate or remain intact in water.
1. Ni(NO3)2(aq) + FeCl3(aq) -->
In this reaction, both Ni(NO3)2 and FeCl3 are in aqueous (dissolved) form. Ni(NO3)2 dissociates into Ni^2+ and 2NO3^- ions, while FeCl3 dissociates into Fe^3+ and 3Cl^- ions. The balanced molecular equation is:
Ni(NO3)2(aq) + 2FeCl3(aq) --> NiCl2(aq) + 2Fe(NO3)3(aq)
To write the net ionic equation, we exclude the spectator ions (ions that appear on both sides unchanged). In this case, the spectator ions are NO3^- and Cl^-. The net ionic equation is:
Ni^2+(aq) + 2Fe^3+(aq) --> Ni^2+(aq) + 2Fe^3+(aq)
2. Ba(ClO4)2(aq) + Na2SO4(aq) -->
Ba(ClO4)2 is in the aqueous form, while Na2SO4 is also in the aqueous form. Both compounds are soluble, and they dissociate into their respective ions. The balanced molecular equation is:
Ba(ClO4)2(aq) + Na2SO4(aq) --> BaSO4(s) + 2NaClO4(aq)
The net ionic equation can be written by excluding the spectator ions (Ba^2+ and ClO4^- ions), giving us:
Ba^2+(aq) + SO4^2-(aq) --> BaSO4(s)
3. 2NH4Br(aq) + Pb(ClO3)2(aq) -->
NH4Br is in the aqueous form, and Pb(ClO3)2 is also in the aqueous form. Both compounds are soluble, so they dissociate into ions. The balanced molecular equation is:
2NH4Br(aq) + Pb(ClO3)2(aq) --> 2NH4ClO3(aq) + PbBr2(s)
To write the net ionic equation, we need to exclude the spectator ions (NH4+ and ClO3^- ions), resulting in:
2Br^-(aq) + Pb^2+(aq) --> PbBr2(s)
4. 2NaOH(aq) + Ba(ClO4)2(aq) -->
NaOH is in the aqueous form, and Ba(ClO4)2 is also in the aqueous form. NaOH is a strong base and dissociates completely into Na+ and OH- ions. Ba(ClO4)2 is soluble and dissociates into Ba^2+ and 2ClO4^- ions. The balanced molecular equation is:
2NaOH(aq) + Ba(ClO4)2(aq) --> Ba(OH)2(s) + 2NaClO4(aq)
To write the net ionic equation, we eliminate the spectator ions (Na+ and ClO4^-), giving us:
2OH^-(aq) + Ba^2+(aq) --> Ba(OH)2(s)
Remember, when writing net ionic equations, it's important to indicate the state of substances involved (solid, liquid, gas, or aqueous) and eliminate spectator ions to focus on the actual chemical reaction taking place.