A block of wood experiences a normal force of 32 N from a rough,flat surface.there is a rope tied to the block.the rope is pulled parallel to the surface and the tension in the rope can be increased to 8 N before the block starts to slide.
Determine the coefficient of static friction
Fn = 32 N. = Normal force.
Fap = 8 N. = Force applied.
Fap-Fs = M*a.
8-Fs = M*0 = 0.
Fs = 8 N. = Force of static friction.
Fs = u*Fn = 8.
u*32 = 8.
u = 0.25.
To determine the coefficient of static friction, we can use the equation:
μs = Fs / N
Where:
μs = coefficient of static friction
Fs = force of static friction
N = normal force
In this case, the normal force is given as 32 N. The maximum tension in the rope before the block starts to slide is 8 N, which is equal to the force of static friction. Therefore, the force of static friction is 8 N.
Plugging in these values into the equation, we have:
μs = 8 N / 32 N
Simplifying this, we get:
μs = 0.25
Therefore, the coefficient of static friction is 0.25.
To determine the coefficient of static friction, we need to use the equation relating the maximum force of static friction (Fs) to the normal force (Fn), which is given by Fs = μsFn, where μs is the coefficient of static friction.
In this case, the normal force is 32 N. We also know that the tension in the rope can be increased to 8 N before the block starts to slide. The tension in the rope represents the force required to overcome the maximum force of static friction.
So, we have:
Fs = 8 N
Fn = 32 N
Now, we can rearrange the equation to solve for the coefficient of static friction:
μs = Fs / Fn
Substituting the values we have:
μs = 8 N / 32 N
μs = 0.25
Therefore, the coefficient of static friction is 0.25.