A graduated cylinder contains 17.0 mL of water. What is the new water level after 31.6 g of silver metal with a density of 10.5 g/mL is submerged in the water
What is the volume of the silver metal? That's volume = mass/density = ?
Then that volume will displace the water in the graduated cylinder the same amount so 17.0 + volume Ag = new volume in mL.
To find the new water level after the silver metal is submerged, we need to use the principle of displacement. Here's how you can solve it:
1. Determine the volume of the silver metal:
Density = Mass / Volume
Rearrange the formula to solve for Volume:
Volume = Mass / Density
Volume = 31.6 g / 10.5 g/mL
Volume = 3.01 mL
2. Calculate the total volume after the silver metal is submerged:
New Volume = Initial Volume of Water + Volume of Silver Metal
New Volume = 17.0 mL + 3.01 mL
New Volume = 20.01 mL
Therefore, the new water level in the graduated cylinder after the silver metal is submerged is 20.01 mL.