Joe will rent a car for the weekend. He can choose one of two plans. The first plan has no initial fee but costs
$0.90
per mile driven. The second plan has an initial fee of
$65
and costs an additional
$0.40
per mile driven. How many miles would Joe need to drive for the two plans to cost the same?
let m be the number of miles
case1: cost = .9m
case2: cost = 65 + .4m
so you want :
.9m = 65 + .4m
.5m = 65
m = 130
550
To find the number of miles Joe would need to drive for the two plans to cost the same, we can set up an equation.
Let's assume Joe drives x miles.
For the first plan, the cost is $0.90 per mile driven. So the cost of the first plan would be 0.9x.
For the second plan, there is an initial fee of $65, and then it costs an additional $0.40 per mile driven. So the cost of the second plan would be 65 + 0.4x.
We can set up the equation:
0.9x = 65 + 0.4x
Now, we can solve for x.
Subtract 0.4x from both sides of the equation:
0.9x - 0.4x = 65
0.5x = 65
Divide both sides by 0.5:
x = 130
Therefore, Joe would need to drive 130 miles for the two plans to cost the same.