How many moles of chloride ions are in 100mL of a 0.3molar solution of AlCl3?
#moles Cl =(.3M AlCl3)(.1L)(105g/mol / 132g/m0l)
Close but I don't think so.
mols AlCl3 = M x L = 0.3M x 0.1L = ?
Then mols Cl^- is 3x that. . I don't think you need to convert to grams; the problem asks for mols.
0.35
To find the number of moles of chloride ions in the solution, we can use the formula:
moles = (Molarity) x (Volume) x (Molar mass of chloride ions / Molar mass of AlCl3)
Given:
Molarity (AlCl3) = 0.3 M
Volume = 100 mL = 0.1 L
Molar mass of chloride ions = 35.5 g/mol
Molar mass of AlCl3 = 133.5 g/mol
Substituting the values into the formula:
moles = (0.3 M) x (0.1 L) x (35.5 g/mol / 133.5 g/mol)
Simplifying the expression:
moles = (0.3) x (0.1) x (35.5 / 133.5)
= 0.003 moles
Therefore, there are 0.003 moles of chloride ions in 100 mL of a 0.3 molar solution of AlCl3.
To find the number of moles of chloride ions in a solution of AlCl3, we first need to understand the molecular formula of AlCl3. AlCl3 is made up of one aluminum atom (Al) and three chloride ions (Cl-).
Given that the solution has a concentration of 0.3 moles per liter (0.3M) and a volume of 100 mL (0.1 L), we can use the following steps to calculate the number of moles of chloride ions:
1. Convert the volume from milliliters (mL) to liters (L).
100 mL = 0.1 L
2. Multiply the concentration by the volume to find the number of moles of AlCl3.
moles AlCl3 = 0.3M x 0.1 L = 0.03 moles
3. Since AlCl3 contains three chloride ions for every one molecule, we need to multiply the number of moles of AlCl3 by the ratio of chloride ions to AlCl3.
moles Cl- = 0.03 moles AlCl3 x (3 moles Cl- / 1 mole AlCl3)
moles Cl- = 0.03 moles x 3
moles Cl- = 0.09 moles
Therefore, there are 0.09 moles of chloride ions in 100 mL of a 0.3 molar solution of AlCl3.