if area of rectangular plot is 1250 sq cm. a smaller rectangular plot with area 1/5 of the total area and length is 7 times of its breath, find the perimeter of the smaller plot

If the smaller plot has width w, then

w*7w = 1250/5
7w^2 = 250
w = 5.976

so, its perimeter is 2(w+7w) = 95.6

To find the perimeter of the smaller rectangular plot, we first need to determine its dimensions. Given that the area of the smaller plot is one-fifth of the total area and the length is 7 times the breadth, we can set up the following equations:

Let L be the length of the smaller plot and B be the breadth of the smaller plot.

Equation 1: L * B = 1/5 * (1250)

Since we know that the length is 7 times the breadth, we can also write:

Equation 2: L = 7B

Now, we can substitute Equation 2 into Equation 1:

(7B) * B = 1/5 * (1250)

Simplifying this equation, we have:

7B^2 = 1/5 * 1250

Multiplying both sides by 5 to eliminate the fraction, we get:

35B^2 = 1250

Dividing both sides by 35, we have:

B^2 = 1250 / 35

B^2 = 35.71

Taking the square root of both sides, we find:

B ≈ 5.98

Since the dimensions of the smaller rectangular plot are approximately Length (L) = 7 * 5.98 ≈ 41.86 and Breadth (B) ≈ 5.98, we can calculate its perimeter as follows:

Perimeter = 2L + 2B
Perimeter ≈ 2 * 41.86 + 2 * 5.98
Perimeter ≈ 83.72 + 11.96
Perimeter ≈ 95.68 cm

Therefore, the perimeter of the smaller rectangular plot is approximately 95.68 cm.