6.5g of zinc was reacted with excess HCL.calculate the volume of dry hydrogen gas.
my work
zn+2HCL-zncl2 + H2
To calculate the volume of dry hydrogen gas produced, you need to use the ideal gas law equation:
PV = nRT
Where:
P is the pressure of the gas (in atm)
V is the volume of the gas (in liters)
n is the number of moles of the gas
R is the ideal gas constant (0.0821 L·atm/(mol·K))
T is the temperature of the gas (in Kelvin)
First, you need to find the number of moles of hydrogen gas produced. From the balanced equation, you can see that 1 mole of zinc reacts with 1 mole of hydrogen gas. Therefore, the number of moles of hydrogen gas produced is equal to the number of moles of zinc reacted.
To calculate the number of moles of zinc:
Given mass of zinc = 6.5 g
Molar mass of zinc (Zn) = 65.38 g/mol (from the periodic table)
Number of moles of zinc = mass / molar mass
Number of moles of zinc = 6.5 g / 65.38 g/mol
Number of moles of zinc = 0.0994 mol
Since the reaction is performed under excess HCl, the number of moles of hydrogen gas produced is also 0.0994 mol.
Now, let's assume the temperature and pressure conditions for the reaction. Let's say it is performed at room temperature (25°C or 298 K), and atmospheric pressure (1 atm).
Substituting the values into the ideal gas law equation:
PV = nRT
V = nRT / P
V = (0.0994 mol) * (0.0821 L·atm/(mol·K)) * (298 K) / (1 atm)
V = 2.47 L
Therefore, the volume of dry hydrogen gas produced is approximately 2.47 liters.
To calculate the volume of dry hydrogen gas produced, we need to use the ideal gas law equation, which states:
PV = nRT
Where:
P = pressure of the gas
V = volume of the gas
n = number of moles of the gas
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature in Kelvin
First, we need to determine the number of moles of hydrogen gas produced. We know that 6.5g of zinc was reacted, so we need to find the number of moles of zinc. The molar mass of zinc (Zn) is 65.38 g/mol.
Number of moles of zinc = mass / molar mass
Number of moles of zinc = 6.5g / 65.38 g/mol
Number of moles of zinc = 0.0994 mol
According to the balanced equation, 1 mole of zinc reacts to produce 1 mole of hydrogen gas (H2). Therefore, the number of moles of hydrogen gas produced is also 0.0994 mol.
Now, we can use the ideal gas law equation to calculate the volume of the gas. Let's assume the pressure and temperature are constant, just to simplify the calculation.
PV = nRT
Volume of gas = (nRT) / P
Substituting the values into the equation:
Volume of gas = (0.0994 mol * 0.0821 L·atm/(mol·K) * T) / P
To obtain the value in liters, we need to convert the temperature to Kelvin and provide the pressure value in atm.
Make sure to substitute the temperature and pressure values into the equation to get an accurate volume of the dry hydrogen gas.
so clearly each mole of Zn produces 1 mole of H2
6.5g = 0.1 mole Zn
So, since 1 mole of H2 occupies 22.4L at STP, ...