A car travels 3.0km due south and then 4.0km due west.what is it displacement from the starting point?
How do you get A=36.90
To find the displacement from the starting point, we can use the Pythagorean theorem.
Let's assign the south direction as the negative y-axis and the west direction as the negative x-axis. So, the 3.0 km south would be (-3.0, 0) and the 4.0 km west would be (0, -4.0).
Using the Pythagorean theorem, the displacement can be calculated as:
Displacement = √(change in x)^2 + (change in y)^2
Change in x = 0 - (-4.0) = 4.0
Change in y = 0 - (-3.0) = 3.0
Displacement = √(4.0)^2 + (3.0)^2
Displacement = √16.0 + 9.0
Displacement = √25.0
Displacement = 5.0 km
Therefore, the displacement from the starting point is 5.0 km.
To find the displacement from the starting point, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the car has traveled 3.0 km due south and 4.0 km due west. These distances form the two sides of a right triangle. We can consider the southward distance as the vertical side (opposite the right angle) and the westward distance as the horizontal side (adjacent to the right angle).
Using the Pythagorean theorem, we can calculate the displacement as follows:
Displacement = √(3.0^2 + 4.0^2)
Simplifying the equation:
Displacement = √(9 + 16)
Displacement = √25
Displacement = 5.0 km
Therefore, the displacement from the starting point is 5.0 km.
X = -4 km.
Y = -3.0 km.
Q3.
Tan A = Y/X = -3/-4 = 0.750
A = 36.9o S of W. = 216.9o CCW. = Direction.
Disp. = X/Cos216.9 = -4/Cos216.9=5.0 km.