if two forces 10N and 20N are inclined at angle 60degree to each other. Find the resultant force.

if two forces 10N and 20N are inclined at angle 60degree to each other. Find the resultant force.

R^2= a^2+c^2-2ac cos(180 - THETA) Theta in this case is 60, 180-60=120

R^2 = 10^2 + 20^2 – (2 x 10 x 20 cos 120)
R^2 = 700N
R=√700N
R= √100 * √7 N
R= 10*√7 N or 10√7N

R=f1+f2=10+20(both in square) R=100+400=500.(find the square root)=22.4n.therefore resultant force is 22.4n

R=20^2+10^ -2of10cos[120]=400+100-400[-0.5]=500+200=700

NOT CLEAR ENOUGH

Please

Good

R²=400 +100 - 400cos120

=500+200
√700
R=26.5N

R²=a²+b²-2ab cos theta

But R?
a=10N
b=20N
Theta=(180-60)=120°
R²=10²+20²-2×10×20 cos 120°
=100+400-400(0.5)
=500+400×0.5
=500+200
=700
R²=√700
=26.5N,,

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