3x-2y=8

5x-2y=9

using elimination method.. please help.

If you subtract the bottom from the top, you eliminate y, leaving

-2x = -1

Now you have x, and you can use that value to find y.

Aren't we suppose to get rid of the -2 to get x.. by dividing on both sides?

using elimination method, what is the value of x in the equations 3x - 2y = 8 and 5x + y = 9?

using determinant method, what is the value of x in the equations 3x + 2y = "-10" and 5x + 3y = "-16?"

using determinant method, what is the value of x in the equations 3x + 2y = "-10" and 5x + 3y = "-16?"

To solve this system of equations using the elimination method, we will eliminate one of the variables by adding or subtracting the equations. Here's how you can do it step by step:

Step 1: Examine the equations
Given equations:
3x - 2y = 8 ...(Equation 1)
5x - 2y = 9 ...(Equation 2)

Notice that both equations have "-2y". We can eliminate "-2y" by subtracting Equation 1 from Equation 2.

Step 2: Subtract the equations
Subtract Equation 1 from Equation 2:
(5x - 2y) - (3x - 2y) = 9 - 8

This simplifies to:
5x - 2y - 3x + 2y = 1

After eliminating "-2y", we are left with:
5x - 3x = 1

Simplifying further, we get:
2x = 1

Step 3: Solve for x
Divide both sides of the equation by 2 to solve for x:
2x/2 = 1/2
x = 1/2

Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y.

Step 4: Substitute x into an equation
Let's substitute x = 1/2 into Equation 1:
3(1/2) - 2y = 8

Simplifying this equation gives us:
3/2 - 2y = 8

Step 5: Solve for y
To solve for y, we need to isolate the variable. Let's subtract 3/2 from both sides:
3/2 - 3/2 - 2y = 8 - 3/2
-2y = 13/2

Divide both sides by -2:
(-2y)/-2 = (13/2)/-2
y = -13/4

Therefore, the solution to the system of equations is x = 1/2 and y = -13/4.