Use method II to simplify the following complex rational expression.

5-13/x-2 divided by 6/x-2-7. I'm not sure if this is the proper set up, but it's suppose to be a division on top and bottom. Please if someone could help

I'll take a guess at just what you mean:

5 - 13/(x-2)
----------------------
6/(x-2) - 7

In both the numerator and denominator, put everything over a common denominator

[5(x-2)-13]/(x-2)
-----------------------
[6-7(x-2)]/(x-2)

Since the denominators are the same, they can be eliminated. When dividing by a fraction, you multiply by its reciprocal, so the (x-2) factors will cancel. That leaves you with

(5x-23)/(24-7x)

go to the website wolframalpha (google it) and copy and paste this: [5-(13)/(x-2)] ÷ [(6)/(x-2)-7]

im assuming that's what you mean by the equation. if that is how your equation looks like then your answer for x should be x = 23/3 ?????

if i got it wrong, try using the website wolframalpha a lot of college students use this website, but you need to know how to type in the equations.

woops, i mean 23/5

To simplify the given complex rational expression using Method II, we need to find a common denominator for both fractions in the expression.

The expression is: (5 - 13/(x - 2)) / (6/(x - 2) - 7)

Step 1: Find the least common denominator (LCD) of the fractions in both the numerator and denominator.

The LCD is the least common multiple (LCM) of the denominators. In this case, the denominators are (x - 2) and (x - 2).

The LCM of (x - 2) and (x - 2) is (x - 2).

Step 2: Rewrite the expression using the LCD.

The numerator becomes (5(x - 2) - 13) and the denominator becomes 6 - 7(x - 2).

So, the simplified expression becomes: (5(x - 2) - 13) / (6 - 7(x - 2))

Step 3: Simplify the expression further if possible.

To simplify, distribute and combine like terms.

Numerator: 5(x - 2) - 13 = 5x - 10 - 13 = 5x - 23
Denominator: 6 - 7(x - 2) = 6 - 7x + 14 = 20 - 7x

The simplified expression is: (5x - 23) / (20 - 7x)

This is the simplified form of the complex rational expression using Method II.