A student adds 3 spoons of salt to 100 ml of water. The solution is clear with nothing on the bottom of the cup. One spoon of the salt has a mass of 5g. What is the mass of the solution? After the water evaporates what is the mass of the solid remaining in the cup?

5G

15g

To determine the mass of the solution and the mass of the solid remaining in the cup, we can calculate using the given information.

1. Mass of salt in the solution:
Since one spoon of salt has a mass of 5g, and the student adds 3 spoons of salt, the total mass of salt in the solution is:
3 spoons * 5g/spoon = 15g

2. Mass of water in the solution:
The student adds 100 ml of water to the solution, and since the density of water is approximately 1 g/ml, the mass of the water in the solution is:
100 ml * 1 g/ml = 100g

3. Mass of the solution:
The mass of the solution is the sum of the mass of salt and the mass of water:
Mass of solution = Mass of salt + Mass of water
Mass of solution = 15g + 100g = 115g

Therefore, the mass of the solution is 115g.

4. Mass of the solid remaining after evaporation:
When the water evaporates, the salt will remain in the cup. So the mass of the solid remaining is equal to the mass of the initial salt added to the solution, which is 15g.

Therefore, the mass of the solid remaining in the cup after the water evaporates is 15g.