ec bisects <bed,

m<<aeb =11x-12
and m<ced =4x+1.
Find m<aec

ec bisects <bed,

m<<aeb =11x-12
and m<ced =4x+1.
Find m<aec

To find the measure of angle <aec, we first need to find the measures of <bed, <ced, and <aec.

Given:
- Angle bisector ec bisects angle <bed.

We know that when a line bisects an angle, it divides the angle into two equal parts.

Therefore, m<bed = m<ced.

Let's equate the measures of <bed and <ced to find the value of 'x':

m<bed = m<ced

11x - 12 = 4x + 1

Simplifying the equation:

11x - 4x = 1 + 12

7x = 13

Dividing both sides by 7:

x = 13/7

Now that we have the value of 'x', we can substitute it back into the equation to find m<aec:

m<aeb = 11x - 12
m<aeb = 11(13/7) - 12
m<aeb = 143/7 - 84/7
m<aeb = 59/7

Since ec bisects <bed, the measure of <aec is equal to half the measure of <bed:

m<aec = (1/2) * m<bed
m<aec = (1/2) * (59/7)
m<aec = 59/14

Therefore, m<aec = 59/14.

To find the measure of angle <aec, we can use the property of angles formed by a transversal intersecting two parallel lines. In this case, <bed and <ced are both formed by the transversal ec and the parallel lines ae and bd.

Since ec bisects <bed, we can say that m<bec = m<dec. Let's call this angle measure "y."

We know that m<aeb = 11x-12 and m<ced = 4x+1. We need to find the value of "x" to determine the measure of angle <aec.

To find the value of "x," we can set up an equation:

m<aeb + m<aec = 180° (since they form a straight angle)

Substituting the angle measures we know:

11x-12 + y = 180°

Similarly, for angle <ced and angle <aec:

m<ced + m<aec = 180°

4x+1 + y = 180°

Now we have two equations:

11x-12 + y = 180°
4x+1 + y = 180°

Solving these two equations will give us the values of "x" and "y." Once we have those values, we can substitute them into the equation m<aec = x+y to find the measure of angle <aec.

Point a could be anywhere. Where does it lie in relation to b,c,d?