You make a solution using a solute (5g) in water (total volume 100ml). The molar mass of the solute is 110 g/mol.
What is the molarity?
What is the concentration reported as % by mass?
% w/w = (mass solute/mass solution). You don't have the mass of the solution nor do you have a way of determining it.
For molarity.
mols solute = grams solut/molar mass solute.
Then M = mols/L solution = mols solute/0.1 L = ?
To calculate the molarity (M) of a solution, you need to know the number of moles of solute and the volume of the solution in liters.
First, convert the mass of the solute to moles using the molar mass.
Number of moles = mass of solute (g) / molar mass (g/mol)
Number of moles = 5 g / 110 g/mol
Number of moles = 0.04545 mol
Next, convert the volume of the solution from milliliters to liters.
Volume of solution = 100 ml / 1000 ml/L
Volume of solution = 0.1 L
Finally, divide the number of moles by the volume to calculate the molarity.
Molarity (M) = Number of moles / Volume of solution
Molarity (M) = 0.04545 mol / 0.1 L
Molarity (M) = 0.4545 M
So, the molarity of the solution is 0.4545 M.
To calculate the concentration of the solution reported as a percent by mass, you need to know the mass of the solute and the total mass of the solution.
First, calculate the total mass of the solution by adding the mass of the solute to the mass of the solvent.
Total mass of solution = mass of solute + mass of solvent
Total mass of solution = 5 g + 100 g
Total mass of solution = 105 g
Next, calculate the percent by mass by dividing the mass of the solute by the total mass of the solution and multiplying by 100.
% by mass = (mass of solute / total mass of solution) x 100
% by mass = (5 g / 105 g) x 100
% by mass = 4.76%
So, the concentration of the solution reported as % by mass is 4.76%.