A boy sledding down a hill accelerates at 2.33
m/s2
.
If he started from rest, in what distance
would he reach a speed of 8.70 m/s?
Answer in units of m
To find the distance the boy would reach a speed of 8.70 m/s, we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final speed = 8.70 m/s
u = initial speed = 0 m/s (as the boy started from rest)
a = acceleration = 2.33 m/s^2
s = distance
Rearranging the equation, we have:
s = (v^2 - u^2) / (2a)
Substituting the given values, we get:
s = (8.70^2 - 0^2) / (2 * 2.33)
Simplifying the equation further:
s = (75.69 - 0) / 4.66
s = 75.69 / 4.66
s ≈ 16.26 m
Therefore, the boy would reach a speed of 8.70 m/s in approximately 16.26 meters.