A bullet is fired straight up from a gun with a muzzle velocity of 217 m/s. Neglecting air resistance, what will be its displacement after 9 s? The acceleration of gravity is 9.8 m/s2 .
2349.9
To determine the displacement of a bullet fired straight up, we can use the equation of motion for vertical motion.
The equation for displacement in vertical motion is given by:
Δy = V₀t + (1/2)at²
Where:
Δy = displacement
V₀ = initial velocity
t = time
a = acceleration
In this case, the bullet is fired straight up, so it will have an initial velocity of +217 m/s (upwards) and acceleration due to gravity will be -9.8 m/s² (downwards).
Given that the bullet is fired upwards, we can take the initial velocity as positive. Therefore, the equation becomes:
Δy = 217t - (1/2) * 9.8 * t²
Substituting the given time, t = 9 s, into the equation:
Δy = 217 * 9 - (1/2) * 9.8 * (9)²
Calculating this equation:
Δy = 1953 - (1/2) * 9.8 * 81
Δy = 1953 - 396.9
Δy = 1556.1
Therefore, after 9 seconds, the displacement of the bullet will be 1556.1 meters upwards.