In jims,5 times as many students take the bus as those who walk. A total of 24 students walk or take the bus. How many more students take the bus than walk to school?

well, 4+20 = 24

16

To solve this problem, we can use a system of equations. Let's assume that the number of students who walk to school is represented by "w," and the number of students who take the bus is represented by "b."

According to the problem, "5 times as many students take the bus as those who walk." So, we can express this relationship in an equation:

b = 5w

We are also given that "a total of 24 students walk or take the bus." This can be written as:

b + w = 24

Now we have a system of equations that we can solve simultaneously to find the values of "w" and "b."

Substituting the first equation into the second equation, we get:

5w + w = 24
6w = 24
w = 4

Now, substitute the value of w back into the first equation to find b:

b = 5(4)
b = 20

So, there are 4 students who walk to school and 20 students who take the bus. To find how many more students take the bus than walk to school, subtract the number of students who walk from the number of students who take the bus:

20 - 4 = 16

Therefore, there are 16 more students who take the bus than walk to school.