A bear spies some honey and takes off from rest, accelerating at a rate of 2.8 m/s^2. If the honey is 20m away, How fast will the bear be going when he gets to the honey?
v = √(2as)
so, just plug in the numbers
To find the speed at which the bear will be going when it reaches the honey, we can use the equation of motion:
v^2 = u^2 + 2as
where:
v = final velocity (what we need to find)
u = initial velocity (0, since the bear starts from rest)
a = acceleration (2.8 m/s^2)
s = displacement (20m)
First, let's find the value of v^2:
v^2 = 0^2 + 2 * 2.8 * 20
v^2 = 0 + 56
v^2 = 56
Now, we can find the value of v by taking the square root of both sides of the equation:
v = √(56)
v ≈ 7.48 m/s
Therefore, the bear will be going at approximately 7.48 m/s when it reaches the honey.