1)Johnny Football throws a football straight up in the air. It travels to a maximum height of 7.1 m. It then falls and is caught at the exact location where it was released 2.4 seconds later. a) What was the ball's average speed during this entire toss? b) What was the ball's average velocity during this entire toss? (Hint: Look at your definitions of average speed and velocity!

To find the answers, we need to understand the definitions of average speed and average velocity.

Average speed is the total distance traveled divided by the total time taken. It is a scalar quantity that only considers magnitude.

Average velocity, on the other hand, is the displacement divided by the total time taken. It is a vector quantity that considers both magnitude and direction.

a) To find the ball's average speed during the entire toss, we need to calculate the total distance traveled. Since the ball goes up to a maximum height of 7.1 m and comes back to the same location, the total distance traveled is twice the height, which is 2 * 7.1 m = 14.2 m.

Next, we divide this distance by the total time taken, which is given as 2.4 seconds. Therefore, the ball's average speed is 14.2 m / 2.4 s = 5.92 m/s.

b) To find the ball's average velocity during the entire toss, we need to calculate the displacement. Displacement is a vector quantity that represents the change in position. In this case, the ball starts and ends at the same position, so the displacement is zero.

Since the displacement is zero and the total time taken is given, we can say that the ball's average velocity is also zero.

In summary:
a) The ball's average speed during the entire toss is 5.92 m/s.
b) The ball's average velocity during the entire toss is 0 m/s.