a box weighing 800n is dragged across a level floor at a constant speed under the influence of a 60n applied force.What is the coefficient of sliding friction between the box and the floor?
M*g = 800 N. = Normal(Fn).
Fap-Fk = M*a.
60-u*800 = M*0 = 0.
u*800 = 60.
u = 0.075.
To find the coefficient of sliding friction between the box and the floor, we need to use the equation:
Frictional force = Coefficient of sliding friction x Normal force
The normal force is equal to the weight of the box, which is 800 N. Therefore, the equation becomes:
Frictional force = Coefficient of sliding friction x 800 N
We are given that the applied force is 60 N, and the box is being dragged at a constant speed. At constant speed, the applied force is equal to the frictional force. Therefore:
60 N = Coefficient of sliding friction x 800 N
To solve for the coefficient of sliding friction, we rearrange the equation:
Coefficient of sliding friction = 60 N / 800 N
Using a calculator, we can calculate the coefficient of sliding friction to be:
Coefficient of sliding friction = 0.075
To find the coefficient of sliding friction between the box and the floor, you need to use the equation:
Frictional Force = Coefficient of Friction * Normal Force
In this case, the normal force is equal to the weight of the box, which is 800 N. The applied force of 60 N is canceling out some of the weight, so the normal force remains 800 N.
The frictional force is equal to the applied force because the box is being dragged at a constant speed, indicating that there is no acceleration. So, the frictional force is 60 N.
Now, we can plug the values into the equation:
60 N = Coefficient of Friction * 800 N
Now, we can solve for the coefficient of friction:
Coefficient of Friction = 60 N / 800 N
Coefficient of Friction = 0.075
Therefore, the coefficient of sliding friction between the box and the floor is 0.075.