Sue is 8 years older than her pet goldfish Maya .In two years Sue's age will be three times Maya's age .What are their present age?
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To find out Sue and Maya's present ages, we can set up a system of equations based on the given information. Let's call Sue's present age "S" and Maya's present age "M."
Based on the information given, we know that Sue is 8 years older than her pet goldfish Maya, so we can write the equation:
S = M + 8
We also know that in two years, Sue's age will be three times Maya's age, so we can write the equation:
S + 2 = 3(M + 2)
Now we have a system of two equations:
S = M + 8
S + 2 = 3(M + 2)
To solve this system, we can use substitution or elimination method. Let's solve it using the substitution method.
Start by rearranging the first equation for S:
S = M + 8
Substitute this value of S in the second equation:
(M + 8) + 2 = 3(M + 2)
Now solve for M:
M + 10 = 3M + 6
10 - 6 = 3M - M
4 = 2M
M = 4/2
M = 2
Now substitute the value of M back into the first equation to find S:
S = M + 8
S = 2 + 8
S = 10
So, Sue's present age (S) is 10 years and Maya's present age (M) is 2 years.