Vince
posted by Joey .
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Determine the final end (final) value of n in a hydrogen atom transition, if electron starts in n = 1 and the atom absorbs a photon of light with an energy of 2.044 X 10^18J?
thank you very much for your help

Vince 
Joey
1/wavelength = 1.9678 X 10^7 m^1 (1/11/n^2)
1/9.68 X 10^8 = 1.09678 X 10^7 m^1(11/n^2)
Is this right , how to solve the rest ? 
??? 
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Vince 
Noor Whayeb
Determine the final end (final) value of n in a hydrogen atom transition, if electron starts in n = 1 and the atom absorbs a photon of light with an energy of 2.044 X 10^18J?
Here's the solution :)
1/wavelength= Rh(1/n1^21/n2^2)
speed of light = wavelength X frequency
wavelength= speed/frequency
Rh = 1.09678 X 10^7 (M1)
Energy = H X V
2.044 X 10^18 = 6.626 X 10^34 X V

V= 3.085 X 10^15

1/wavelength =1.09678 X 10^7 (11/n2^2)
1/speed/frequency = RH ( 1 1/n2^2)
frequency/Speed X RH = (11/n2^2)
3.085 X 10^15 / 3 X 10^8 X 1.09687 X 10^7 =(11/n2^2)
3.085 X 10^15 X 10^8 X 10 ^7 / 3 X 1.09678 = (1 1/n2^2)
0.938 = (1 1/n2^2)
1/n2^2 = 10.938 = 0.062
n2^2 = 1/0.062 = 16
n = 4
you welcome
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