# Vince

posted by Joey

Determine the final end (final) value of n in a hydrogen atom transition, if electron starts in n = 1 and the atom absorbs a photon of light with an energy of 2.044 X 10^-18J?

thank you very much for your help

1. Joey

1/wavelength = 1.9678 X 10^7 m^-1 (1/1-1/n^2)

1/9.68 X 10^-8 = 1.09678 X 10^7 m^-1(1-1/n^2)

Is this right , how to solve the rest ?

2. Writeacher

If you followed directions and put your SUBJECT in the School Subject box, a math/science tutor might have answered your questions by now.

3. Noor Whayeb

Determine the final end (final) value of n in a hydrogen atom transition, if electron starts in n = 1 and the atom absorbs a photon of light with an energy of 2.044 X 10^-18J?

Here's the solution :)

1/wavelength= Rh(1/n1^2-1/n2^2)
speed of light = wavelength X frequency
wavelength= speed/frequency

Rh = 1.09678 X 10^7 (M-1)
Energy = H X V
2.044 X 10^-18 = 6.626 X 10^-34 X V
--------------------
V= 3.085 X 10^15
--------------------
1/wavelength =1.09678 X 10^7 (1-1/n2^2)
1/speed/frequency = RH ( 1- 1/n2^2)
frequency/Speed X RH = (1-1/n2^2)
3.085 X 10^15 / 3 X 10^8 X 1.09687 X 10^7 =(1-1/n2^2)

3.085 X 10^15 X 10^-8 X 10 ^-7 / 3 X 1.09678 = (1- 1/n2^2)
0.938 = (1- 1/n2^2)
1/n2^2 = 1-0.938 = 0.062
n2^2 = 1/0.062 = 16
n = 4

you welcome

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