A military jet fighter plane flying at 180m/s pulls out of a vertical dive by turning upward along a circular path

of radius 860m. What is the acceleration of the plane? Express the acceleration as a multiple ofg.

37.67

To find the acceleration of the plane, we need to use the centripetal acceleration formula:

ac = v^2 / r

where ac is the centripetal acceleration, v is the velocity of the plane, and r is the radius of the circular path.

Given that the velocity of the plane is 180 m/s and the radius is 860 m, we can substitute these values into the formula to calculate the acceleration:

ac = (180 m/s)^2 / 860 m

ac = 32400 m^2/s^2 / 860 m

Simplifying the expression, we get:

ac = 37.674 m/s^2

To express the acceleration as a multiple of g, where g is the acceleration due to gravity at the Earth's surface (approximately 9.8 m/s^2), we divide the centripetal acceleration by g:

ac = 37.674 m/s^2 / 9.8 m/s^2

ac ≈ 3.85 g

Therefore, the acceleration of the plane is approximately 3.85 times the acceleration due to gravity.

To find the acceleration of the plane, we can use the centripetal acceleration formula:

Ac = v^2 / r

where Ac is the centripetal acceleration, v is the velocity, and r is the radius of the circular path.

In this case, the velocity of the plane is given as 180 m/s, and the radius of the circular path is 860 m.

Plugging in the values into the formula, we have:

Ac = (180 m/s)^2 / 860 m

Simplifying this equation gives us:

Ac = 32400 m/s^2 / 860 m

Now, to express the acceleration as a multiple of g, we need to divide the centripetal acceleration by the acceleration due to gravity (g).

The acceleration due to gravity is approximately 9.8 m/s^2.

So, the acceleration of the plane as a multiple of g is:

Ac / g = (32400 m/s^2 / 860 m) / 9.8 m/s^2

Simplifying further, we get:

Ac / g ≈ 34.2857

Therefore, the acceleration of the plane is approximately 34.2857 times the acceleration due to gravity or 34.29g.

a=v^2/r

then number of g's is a/9.8

this is for the plane, the pilot still feels gravity, so the g's the pilot feels will be one more than the number you calculated.