A sample of a copper chloride of mass 1.425g is treated with a water solution of silver nitrate, and the AgCl formed had a mass of 3.038g. What is the correct empirical formula of the copper chloride?
You need to determine the mass Cl in the 1.425 g copper chloride.
mass Cl = mass AgCl x (atomic mass Cl/molar mass AgCl) = 3.038 x (35.45/143.32) = ?
mass Cu = 1.425-mass Cl
Then convert mass Cu to mols.
Convert mass Cl to mols.
Find the ratio. You should get CuCl2 for the empirical formula. Post your work if you get stuck.