How do I write the correct dissolution reaction for BaCl2
Hyb
To write the correct dissolution reaction for BaCl2, you need to understand the properties of the compound and the rules for writing dissolution reactions.
BaCl2 is composed of a barium ion (Ba2+) and two chloride ions (Cl-). When it dissolves in water, it dissociates into its individual ions. Here's how you can write the dissolution reaction step by step:
1. Identify the compound: BaCl2
2. Break down the compound into its ions: Ba2+, Cl-
3. Write the dissociation of the compound: BaCl2(s) -> Ba2+(aq) + 2Cl-(aq)
- "(s)" indicates that BaCl2 is in the solid state initially.
- "(aq)" indicates that the ions are in the aqueous (dissolved) state.
The balanced equation for the dissolution reaction is:
BaCl2(s) -> Ba2+(aq) + 2Cl-(aq)
Remember that the coefficients are not necessary since there is a one-to-one ratio between Ba2+ and Cl-.